Note that since 42 = 16, and since 554 ends in a 4, b must be such that 16 in base b ends in a 4. That means that the remainder when 16 is divided by b is 4. There are then only two possibilities: b = 6 and b = 12.
We then note that in base 10, 242 = 576. Since in base b, 242 = 554, b must be larger than 10. (Try some cases if you don't see why this works.) It thus follows than b = 12. Testing with the actual values, we see that this is correct.
(This can also be solved algebraically, by saying that (2b2 + 4)2 = 5b3 + 5b2 + 4 and solving for b. But the above method is a lot quicker.)
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